You'll have to create a balanced BST. Otherwise, depending on the
order of the dataset, it might degenerate into a linked list, which
doesn't make searching an O(log n) process.

Dave

On Jun 25, 12:07 pm, Anand <[email protected]> wrote:
> The most useful data structure would be BST.
> Each node will have data value and its count. count indicates the number of
> times it is repeated in a sequence. Below is the algo to creat a binary
> search tree.
>
> insert_node(int data, node root)
> {
>    if(root == NULL)
>    {
>        root = malloc();
>        root->right = NULL;
>        root->left = NULL;
>        root->data = data;
>        root->count =1;
>    }
>    else if(root->data == data)
>    {
>       root->count++;
>    }
>    else if(data < root->data)
>      root->left = insert_node(data, root->left);
>    else
>      root->right = insert_node(data, root->right);
>
> }
>
> creation of binary search tree will take O(logn)
> Take inorder traversal of above binary tree to get the sorted sequence in
> O(nlog(logn)) also while doing inorder traversal while printing the root
> value also check the count and repeat value that many time.
> On Fri, Jun 25, 2010 at 5:21 AM, sharad kumar <[email protected]>wrote:
>
>
>
> > You are given an unordered sequence of n integers with many duplications,
> > such that the number of distinct integers in the sequence is O(log n).
> > Design a sorting algorithm and its necessary data structure(s), which can
> > sort the sequence using at most O(n log(log n)) time.
>
> > Give the detailed design.
>
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