@Dave: you mean need to generate an AVL tree instead.

On Fri, Jun 25, 2010 at 12:24 PM, Dave <[email protected]> wrote:

> You'll have to create a balanced BST. Otherwise, depending on the
> order of the dataset, it might degenerate into a linked list, which
> doesn't make searching an O(log n) process.
>
> Dave
>
> On Jun 25, 12:07 pm, Anand <[email protected]> wrote:
> > The most useful data structure would be BST.
> > Each node will have data value and its count. count indicates the number
> of
> > times it is repeated in a sequence. Below is the algo to creat a binary
> > search tree.
> >
> > insert_node(int data, node root)
> > {
> >    if(root == NULL)
> >    {
> >        root = malloc();
> >        root->right = NULL;
> >        root->left = NULL;
> >        root->data = data;
> >        root->count =1;
> >    }
> >    else if(root->data == data)
> >    {
> >       root->count++;
> >    }
> >    else if(data < root->data)
> >      root->left = insert_node(data, root->left);
> >    else
> >      root->right = insert_node(data, root->right);
> >
> > }
> >
> > creation of binary search tree will take O(logn)
> > Take inorder traversal of above binary tree to get the sorted sequence in
> > O(nlog(logn)) also while doing inorder traversal while printing the root
> > value also check the count and repeat value that many time.
> > On Fri, Jun 25, 2010 at 5:21 AM, sharad kumar <[email protected]
> >wrote:
> >
> >
> >
> > > You are given an unordered sequence of n integers with many
> duplications,
> > > such that the number of distinct integers in the sequence is O(log n).
> > > Design a sorting algorithm and its necessary data structure(s), which
> can
> > > sort the sequence using at most O(n log(log n)) time.
> >
> > > Give the detailed design.
> >
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