Good approach Shiv.I think thats the best way to do so.The question does not
strictly say we have consecutive n-1 distinct numbers.So,its not worth
considering that particular case.

On Thu, Jul 29, 2010 at 12:08 AM, Shiv ... <[email protected]> wrote:

> What if the number are not consecutive?
>
> My approach-
> Put the numbers in a hash till a collision occurs.
>
>
> On Wed, Jul 28, 2010 at 9:21 PM, Apoorve Mohan <[email protected]>wrote:
>
>> Solution :
>>
>> 1. Find Xor of numbers from 1 to n-1.
>>
>> 2. Find Xor of the numbers present in the array.
>>
>> 3. Xor the results from step 1 and 2 you will get the repeated number.
>>
>>
>> On Wed, Jul 28, 2010 at 8:46 PM, akshay <[email protected]>wrote:
>>
>>> An array of unsorted numbers n is given with one no.repeated once ie
>>> n-1 distinct nos to find duplicate no. in o(n) complexity
>>>
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>> regards
>>
>> Apoorve Mohan
>>
>>
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Regards,
Ashish

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