I think we can assume a perfect hashing to exist. [Please correct me if I am
wrong]

Implementing one, is a different issue. :))

Other than hashing, we can use BST or Heap. ~ O(klog(n))


On Thu, Jul 29, 2010 at 1:07 PM, sourav <[email protected]> wrote:

> @Shiv
>
> Collision is itself a wel known issue in hashing and much need to be
> done to avoid collision. When you say your appraoch is hash the
> numbers, how do u make sure without knowing the nature of the numbers
> that you can hash them without bringing ing collision of inequal items
> of the array?
>
>
> On Jul 28, 11:38 pm, "Shiv ..." <[email protected]> wrote:
> > What if the number are not consecutive?
> >
> > My approach-
> > Put the numbers in a hash till a collision occurs.
> >
> > On Wed, Jul 28, 2010 at 9:21 PM, Apoorve Mohan <[email protected]
> >wrote:
> >
> >
> >
> > > Solution :
> >
> > > 1. Find Xor of numbers from 1 to n-1.
> >
> > > 2. Find Xor of the numbers present in the array.
> >
> > > 3. Xor the results from step 1 and 2 you will get the repeated number.
> >
> > > On Wed, Jul 28, 2010 at 8:46 PM, akshay <[email protected]
> >wrote:
> >
> > >> An array of unsorted numbers n is given with one no.repeated once ie
> > >> n-1 distinct nos to find duplicate no. in o(n) complexity
> >
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> >
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