sort all 3 arrays. then for any every combination of numbers in 2 arrays
say, a and  b do a binary search for element -(a+b) in the third array. It
would be a O(N^2 logN) algorithm
On Tue, Jan 11, 2011 at 12:04 PM, Decipher <ankurseth...@gmail.com> wrote:

> Given three lists: A, B and C of length n each. Write a function which
> returns true if any 3 three numbers (1 from each list), sum up to zero. Else
> return false, if there is no such combination.
>
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