I think for unsorted lists, it will be O(n^3).

On Tue, Jan 11, 2011 at 1:26 PM, juver++ <avpostni...@gmail.com> wrote:

> There is no need to sort first two arrays.
>
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-- 
Dinesh Bansal
The Law of Win says, "Let's not do it your way or my way; let's do it the
best way."

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