Hii, can you please tell me wat d ques exactly is ??

THanks,
Krishna.

On Wed, Mar 2, 2011 at 9:52 AM, sunny agrawal <[email protected]>wrote:

> @bittu
> Question is about to print entire array in sorted order, not searching an
> element
>
> On Wed, Mar 2, 2011 at 4:13 AM, bittu <[email protected]> wrote:
>
>> @all after 32  Message Discussion I know Everyone is looking for O(N)
>> solution well it seems odd how we can search an element in a O(m*n)
>> matrix in O(n)  but answer of this question is given already in the
>> question that " all row & column are sorted  so why O(n) solution
>> exist "  it really matters & play very important role if one will
>> think out of box....well i think inside the box.not outside...lol
>>
>>
>> here we go  for O(n) Clean ,Elegant ,Simple  & Best Solution as i
>> think for this problem
>>
>>
>>  boolean FindElem(int[][] mat, int elem, int M, int N)
>>  {
>>  int row = 0;
>>  int col = N-1;
>>
>>  while (row < M && col >= 0)
>>  {
>>
>>  if (mat[row][col] == elem)//done
>>  {
>>    return true;
>>  }
>>  else if (mat[row][col] > elem) //obvious as all call  are sorted
>> because all value in col[j] < col[j+1]  given  test below program for
>> searching element 2
>>  {
>>  col--;
>>  }
>>  else // its all same as all row are sorted  so if element not found
>> in a[i][]  then got a[i+1][]  row because all all value in row[i] <
>> row[i+1] its given
>>
>> {                                                                      //
>> test below program for searching element 9
>>     row++;
>>  }
>>
>>  }
>>  return false;
>>
>> }
>>
>> Working Code https://ideone.com/64HJg
>>
>> If u found for any counter test case its failing then plz let me know
>> still  f any has  doubt i will try to explain my best
>>
>>
>> Thanks & Regards
>> Shashank Mani>> "the Best way to escape from The Problem is Solve It"
>>
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>
>
> --
> Sunny Aggrawal
> B-Tech IV year,CSI
> Indian Institute Of Technology,Roorkee
>
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