Sanjay,
Whenever we encounter a break statement does not it means to take the
program counter outside of the current loop.
I am confused a little bit. Someone please clarify.
See the following program
#include<stdio.h>
#include<stdlib.h>
int main(){
int t=4;
for(int i=0;i<5;i++){
if(1){
if(t==6) break;
}
t++;
}
printf("%d",t);
/* Prints 6 */
return 0;
}
~
Oll
On Jun 19, 6:05 pm, sanjay ahuja <[email protected]> wrote:
> i=4 is default case for but there is no break statement after default
> case. There for all cases until break is encountered will be executed.
> so i += 5; makes i=9
> i -= 4; will make i=5
> and then break
> so i is 5
>
>
>
>
>
>
>
>
>
> On Sun, Jun 19, 2011 at 6:29 PM, sahil <[email protected]> wrote:
> > #include<stdio.h>
> > void main()
> > { int i = 4;
>
> > switch (i)
> > {
>
> > default: ;
> > case 3:
> > i += 5;
> > if ( i == 8)
> > {
> > i++;
> > if (i == 9) break;
> > i *= 2;
> > }
> > i -= 4;
> > break;
>
> > case 8:
> > i += 5;
> > break;
> > }
> > printf("i = %d\n", i);
> > }
>
> > output:
>
> > i=5
>
> > how..........? can sme one explain...!!
>
> > --
> > You received this message because you are subscribed to the Google Groups
> > "Algorithm Geeks" group.
> > To post to this group, send email to [email protected].
> > To unsubscribe from this group, send email to
> > [email protected].
> > For more options, visit this group
> > athttp://groups.google.com/group/algogeeks?hl=en.
>
> --
> Sanjay Ahuja,
> Analyst, Financing Prime Brokerage
> Nomura Securities India Pvt. Ltd
--
You received this message because you are subscribed to the Google Groups
"Algorithm Geeks" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/algogeeks?hl=en.
