change 1st line to i = 3 and execute. It will print 9. If i = 4, then the
default case gets executed and then goes to case 3, then i's val will be 9.
Later, it comes out of the switch block and prints the val as 9.
On Mon, Jun 20, 2011 at 4:10 PM, oppilas . <[email protected]>wrote:
> Nick,
> I had just tested the code for confirming my doubt whether break statement
> takes the program counter outside of the first "loop" or not.
>
> int i = 4;
>
> switch (i) {
>
> default: ;
> case 3:
> i += 5;
> if ( i == 8){
> i++;
> * if (i == 9) break; /* Now after executing
> this break should't the program counter go to priintf statement*
> * /* and print 9*
> * * i *= 2;
> }
> i -= 4;
> break;
>
> case 8:
> i += 5;
> break;
> }
> printf("i = %d\n", i);
> }
>
> On Mon, Jun 20, 2011 at 1:30 PM, nicks <[email protected]> wrote:
>
>> what's the problem...when t=6 the break statement gets executed and the
>> control comes out of the for loop......
>>
>> hence prints 6..
>>
>>
>> On Mon, Jun 20, 2011 at 12:05 AM, Oppilas <[email protected]>wrote:
>>
>>> Sanjay,
>>> Whenever we encounter a break statement does not it means to take the
>>> program counter outside of the current loop.
>>> I am confused a little bit. Someone please clarify.
>>> See the following program
>>> #include<stdio.h>
>>> #include<stdlib.h>
>>> int main(){
>>> int t=4;
>>> for(int i=0;i<5;i++){
>>> if(1){
>>> if(t==6) break;
>>> }
>>> t++;
>>> }
>>> printf("%d",t);
>>> /* Prints 6 */
>>> return 0;
>>> }
>>>
>>> ~
>>> Oll
>>> On Jun 19, 6:05 pm, sanjay ahuja <[email protected]> wrote:
>>> > i=4 is default case for but there is no break statement after default
>>> > case. There for all cases until break is encountered will be executed.
>>> > so i += 5; makes i=9
>>> > i -= 4; will make i=5
>>> > and then break
>>> > so i is 5
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> > On Sun, Jun 19, 2011 at 6:29 PM, sahil <[email protected]> wrote:
>>> > > #include<stdio.h>
>>> > > void main()
>>> > > { int i = 4;
>>> >
>>> > > switch (i)
>>> > > {
>>> >
>>> > > default: ;
>>> > > case 3:
>>> > > i += 5;
>>> > > if ( i == 8)
>>> > > {
>>> > > i++;
>>> > > if (i == 9) break;
>>> > > i *= 2;
>>> > > }
>>> > > i -= 4;
>>> > > break;
>>> >
>>> > > case 8:
>>> > > i += 5;
>>> > > break;
>>> > > }
>>> > > printf("i = %d\n", i);
>>> > > }
>>> >
>>> > > output:
>>> >
>>> > > i=5
>>> >
>>> > > how..........? can sme one explain...!!
>>> >
>>> > > --
>>> > > You received this message because you are subscribed to the Google
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>>> >
>>> > --
>>> > Sanjay Ahuja,
>>> > Analyst, Financing Prime Brokerage
>>> > Nomura Securities India Pvt. Ltd
>>>
>>> --
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>>>
>>>
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>
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Regards,
Shachindra A C
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