Yes, that I know, but why last argument is printing 100 instead of 99?

On Wed, Jun 22, 2011 at 7:50 PM, Piyush Sinha <[email protected]>wrote:

> the arguments are passed from right to left in a function...
>
> initially ptr is pointing to location of 98 (i =1)
>
> the last argument ++ptr makes it point to 99 therefore output of *e = 99
>  the second last argument passes pointer to 99 only and then
> increments its location to i=3 i.e 100...therefore output of *d = 99
> and *c = 100
> the second argument is pointing to location of i=3 only and then
> decrements to point to location of i=2..therefore output of *a =100
> and *b =100..
>
> hope you understood the sequence of outputs...:) :)
>
> On 6/22/11, Piyush Sinha <[email protected]> wrote:
> > r u sure the last output is also 100..for me its coming 99
> >
> > On 6/22/11, udit sharma <[email protected]> wrote:
> >> #include<stdio.h>
> >> int main()
> >> {
> >> void print(int *,int *,int *,int *,int *);
> >> static int arr[]={97,98,99,100,101,102,103,104};
> >> int *ptr=arr+1;
> >> print(++ptr,ptr--,ptr,ptr++,++ptr);
> >> return 0;
> >> }
> >> void print(int *a,int *b,int *c,int *d,int *e)
> >> {
> >> printf("%d\t%d\t%d\t%d\t%d\n",*a,*b,*c,*d,*e);
> >> }
> >>
> >> Why the output is:
> >> 100    100    100    99    100
> >>
> >>
> >> --
> >> Regards
> >>  UDIT
> >>  DU- MCA
> >>
> >> --
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> >>
> >
> >
> > --
> > *Piyush Sinha*
> > *IIIT, Allahabad*
> > *+91-8792136657*
> > *+91-7483122727*
> > *https://www.facebook.com/profile.php?id=100000655377926 *
> >
>
>
> --
> *Piyush Sinha*
> *IIIT, Allahabad*
> *+91-8792136657*
> *+91-7483122727*
> *https://www.facebook.com/profile.php?id=100000655377926 *
>
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