Please see this.
http://ideone.com/ZM74d
<http://ideone.com/ZM74d>I tried to print by directly giving 2[*arr] still
it's giving null and 0.000.
Can anyone think of a possible reason?

On Fri, Jun 24, 2011 at 12:55 AM, richa mahajan <[email protected]> wrote:

> i think it ll be compiler dependent becoz comma acts as a sequence pooint
> but not in function calls so semi colon here is a sequnce point and d value
> of an object (ptr here) is being modified more than once (between two seq
> points ) so this is undefined behavior..output will b compiler dependent
>
>
> On Wed, Jun 22, 2011 at 5:55 PM, udit sharma <[email protected]>wrote:
>
>> #include<stdio.h>
>> int main()
>> {
>> void print(int *,int *,int *,int *,int *);
>> static int arr[]={97,98,99,100,101,102,103,104};
>> int *ptr=arr+1;
>> print(++ptr,ptr--,ptr,ptr++,++ptr);
>> return 0;
>> }
>> void print(int *a,int *b,int *c,int *d,int *e)
>> {
>> printf("%d\t%d\t%d\t%d\t%d\n",*a,*b,*c,*d,*e);
>> }
>>
>> Why the output is:
>> 100    100    100    99    100
>>
>>
>> --
>> Regards
>>  UDIT
>>  DU- MCA
>>
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