@Sunny : Excellent !!! Keep posting such nice solutions !! :)

On Sat, Jul 2, 2011 at 1:47 AM, Anika Jain <[email protected]> wrote:

> ohh ok i got it.. thanx :)
>
>
> On Sat, Jul 2, 2011 at 12:48 AM, sunny agrawal <[email protected]>wrote:
>
>> it is (2,4] not [2,4].
>> open interval, close interval ......... consider (i,j] as [i+1,j]
>>
>> because a[i] = sum of values from 0 to i
>> and a[j] = sum of values from 0 to j
>> if a[i] = a[j] then it means sum does not changes between a[i] to a[j]
>>
>> so from i+1 to j there are equal no of 1's and -1's
>> or in other words equal no of 0's and 1's
>>
>>
>> On Sat, Jul 2, 2011 at 12:42 AM, Anika Jain <[email protected]>wrote:
>>
>>> @sunny: in a[2,4] has 2 1s and one 0 then how is it a solution? i mean i
>>> didnt get wen a[i]==a[j] then a[i,j] is a solution case..
>>>
>>> On Fri, Jul 1, 2011 at 4:13 PM, sunny agrawal 
>>> <[email protected]>wrote:
>>>
>>>> Take an array of size of the length of the string.
>>>> fill the array positions with one where string contains 1, and -1 where
>>>> it is 0
>>>>
>>>> Now for each i (1,n-1) perform the following operation
>>>> a[i] = a[i-1] + a[i]
>>>> now a[i] will contains sum of values from a[0] to a[i] in original
>>>> array.
>>>>
>>>> Now only thing remains to find is two indexes in this array such that
>>>> a[i] = a[j]
>>>> where ever this condition is met ( i,j ] is a solution
>>>>
>>>> or if for some i a[i] = 0 in this case [0,i] will be a solution
>>>>
>>>> this can be done using hashing
>>>> hash the values in the array of size 2*n+1. as range of values is -n to
>>>> n and keep track of max interval.
>>>>
>>>>
>>>>
>>>>
>>>> On Fri, Jul 1, 2011 at 3:22 PM, Anantha Krishnan <
>>>> [email protected]> wrote:
>>>>
>>>>> Given a string containing 0's and 1's. One would need to find the
>>>>> longest sub-string such that the count of 0's is equal to the count of 1's
>>>>> in the largest sub string.
>>>>>
>>>>> Regards
>>>>> Anantha Krishnan
>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> Sunny Aggrawal
>>>> B-Tech IV year,CSI
>>>> Indian Institute Of Technology,Roorkee
>>>>
>>>>
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>>
>>
>>
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
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