Oops ...
my method will also not work as probabilities will not be equal !!!

On Wed, Jul 6, 2011 at 11:29 PM, sunny agrawal <[email protected]>wrote:

> For RNG in range [a,b] first thing is that all numbers should be generated
> with equal probability.
> in your case you are considering mid in both the ranges so you can modify
> it like [a,mid],[mid+1,b]
>
> still I think this will work fine as far as the ranges get divided
> equally..
>
> like consider the case
> [3,5] so division will be [3,4],[5] still probabilities will not be equal.
>
> so answer should be
> make b-a calls to rand(0,1) and return a+sum of return values of all the
> calls
>
> On Wed, Jul 6, 2011 at 11:20 PM, Nitish Garg <[email protected]>wrote:
>
>> Describe an implementation of Random(a, b) that only make calls to
>> Random(0, 1)?
>> Well I am thinking this way:
>>
>>    - Divide the range (a,b) in to 2 parts like (a, mid) and (mid, b)
>>    where mid = (a+b)/2
>>    - Select one of the range using a call to Random(0, 1).
>>    - Then continue dividing the new range and selecting a new based on a
>>    call to Random(0, 1) until we have two elements left.
>>    - From the two elements one can easily be selected by a call to
>>    Random(a, b).
>>
>> Is this approach correct? Or something else can be done?
>>
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>
>
>
> --
> Sunny Aggrawal
> B-Tech IV year,CSI
> Indian Institute Of Technology,Roorkee
>
>


-- 
Sunny Aggrawal
B-Tech IV year,CSI
Indian Institute Of Technology,Roorkee

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