&& has higher precedence than || the expression is evaluated as z=j || ( k && i ); hence the output i.e 1 ;)
On Sun, Jul 10, 2011 at 11:06 PM, rShetty <[email protected]> wrote: > #include<stdio.h> > int main() > { > int i=0,j=1,k=1,z=0; > z = j || k && i ; > printf("%d",z); > return 0; > } > > The output is 1 for the above program . > > But according to associativity of logical operators , the evaluation > should be from left to right , But is it taking from right to left ? > What is the exact concept for the program behavior above? > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- best wishes!! Vaibhav Shukla DU-MCA -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
