associativity comes into play when operators are of same precedence. On Sun, Jul 10, 2011 at 11:08 PM, vaibhav shukla <[email protected]>wrote:
> && has higher precedence than || > the expression is evaluated as > z=j || ( k && i ); > hence the output i.e 1 ;) > > > On Sun, Jul 10, 2011 at 11:06 PM, rShetty <[email protected]> wrote: > >> #include<stdio.h> >> int main() >> { >> int i=0,j=1,k=1,z=0; >> z = j || k && i ; >> printf("%d",z); >> return 0; >> } >> >> The output is 1 for the above program . >> >> But according to associativity of logical operators , the evaluation >> should be from left to right , But is it taking from right to left ? >> What is the exact concept for the program behavior above? >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > > > -- > best wishes!! > Vaibhav Shukla > DU-MCA > > -- best wishes!! Vaibhav Shukla DU-MCA -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
