@anika : ur ans will give the sum but will also leave that much amount of
space before printing the sum


one betther idea is to use bitwise


int Mysum(int a,int b)
{
 if(b==0)
    return a;
else
 {
   int sum=a^b;
   int carry=(a&b)<<1;
   return  Mysum(sum,carry);
}


On Wed, Jul 13, 2011 at 4:15 PM, dinesh bansal <[email protected]> wrote:

> never mind...thanks.
>
>
> On Wed, Jul 13, 2011 at 2:29 PM, dinesh bansal <[email protected]>wrote:
>
>> Can you explain how its working?
>>
>> On Wed, Jul 13, 2011 at 1:58 PM, Anika Jain <[email protected]>
>> wrote:
>>  > a better idea is use this:
>> >
>> > int a=9,b=4;
>> > int sum=printf("%*s%*s",a,"",b,"");
>> > printf("%d\n",sum);
>> >
>> >
>> > On Wed, Jul 13, 2011 at 1:52 PM, nicks <[email protected]>
>> wrote:
>> >>
>> >> if someone has better idea...then please suggest that.....
>> >> plz explain how this is calculating sum -->>  sum= (int)&p[b];
>> >>
>> >> On Wed, Jul 13, 2011 at 1:50 PM, nicks <[email protected]>
>> wrote:
>> >>>
>> >>> I am looking for a code which can add without using + sign
>> >>> i searched the net and found the following code......can anyone
>> explain
>> >>> me whats happening in this ??
>> >>>
>> >>> #include<stdio.h>
>> >>> #include<conio.h>
>> >>> int main()
>> >>> {
>> >>> int a=3000,b=20,sum;
>> >>> char *p;
>> >>> p=(char *)a;
>> >>> sum= (int)&p[b]; //adding a & b
>> >>> printf("Answer is :");
>> >>> printf("%d",sum);
>> >>> return 0;
>> >>> }
>> >>
>> >> --
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>> >
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>> >
>>
>>
>>
>>  --
>> Dinesh Bansal
>> The Law of Win says, "Let's not do it your way or my way; let's do it
>> the best way."
>>
>
>
>
> --
> Dinesh Bansal
> The Law of Win says, "Let's not do it your way or my way; let's do it the
> best way."
>
> --
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-- 
  best wishes!!
Vaibhav Shukla
    DU-MCA

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