@vaibhav: no it wont coz its printing empty strings.. nothing will be
printed

On Wed, Jul 13, 2011 at 4:42 PM, vaibhav shukla <[email protected]>wrote:

> @anika : ur ans will give the sum but will also leave that much amount of
> space before printing the sum
>
>
> one betther idea is to use bitwise
>
>
> int Mysum(int a,int b)
> {
>  if(b==0)
>     return a;
> else
>  {
>    int sum=a^b;
>    int carry=(a&b)<<1;
>    return  Mysum(sum,carry);
>
> }
>
>
> On Wed, Jul 13, 2011 at 4:15 PM, dinesh bansal <[email protected]>wrote:
>
>> never mind...thanks.
>>
>>
>> On Wed, Jul 13, 2011 at 2:29 PM, dinesh bansal <[email protected]>wrote:
>>
>>> Can you explain how its working?
>>>
>>> On Wed, Jul 13, 2011 at 1:58 PM, Anika Jain <[email protected]>
>>> wrote:
>>>  > a better idea is use this:
>>> >
>>> > int a=9,b=4;
>>> > int sum=printf("%*s%*s",a,"",b,"");
>>> > printf("%d\n",sum);
>>> >
>>> >
>>> > On Wed, Jul 13, 2011 at 1:52 PM, nicks <[email protected]>
>>> wrote:
>>> >>
>>> >> if someone has better idea...then please suggest that.....
>>> >> plz explain how this is calculating sum -->>  sum= (int)&p[b];
>>> >>
>>> >> On Wed, Jul 13, 2011 at 1:50 PM, nicks <[email protected]>
>>> wrote:
>>> >>>
>>> >>> I am looking for a code which can add without using + sign
>>> >>> i searched the net and found the following code......can anyone
>>> explain
>>> >>> me whats happening in this ??
>>> >>>
>>> >>> #include<stdio.h>
>>> >>> #include<conio.h>
>>> >>> int main()
>>> >>> {
>>> >>> int a=3000,b=20,sum;
>>> >>> char *p;
>>> >>> p=(char *)a;
>>> >>> sum= (int)&p[b]; //adding a & b
>>> >>> printf("Answer is :");
>>> >>> printf("%d",sum);
>>> >>> return 0;
>>> >>> }
>>> >>
>>> >> --
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>>> >
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>>>
>>>
>>>
>>>  --
>>> Dinesh Bansal
>>> The Law of Win says, "Let's not do it your way or my way; let's do it
>>> the best way."
>>>
>>
>>
>>
>> --
>> Dinesh Bansal
>> The Law of Win says, "Let's not do it your way or my way; let's do it the
>> best way."
>>
>> --
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>>
>
>
>
> --
>   best wishes!!
> Vaibhav Shukla
>     DU-MCA
>
>  --
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