i think saurabh you wanted to say this --

x^n=pow(x^n/2)*pow(x^n/2)*(x^(*n*mod2))
--


Amol Sharma
Third Year Student
Computer Science and Engineering
MNNIT Allahabad




On Sat, Jul 30, 2011 at 1:10 PM, Ankur Khurana <[email protected]>wrote:

> use divide and conquer  . logm complexity . . .
>
>
> On Sat, Jul 30, 2011 at 1:09 PM, saurabh singh <[email protected]>wrote:
>
>> o(log n)
>> x^n=pow(x^n/2)*pow(x^n/2)*(x^mod2)
>>
>> the base case pow(x,1)=x  pow(x,0)=1
>>
>> On Sat, Jul 30, 2011 at 1:02 PM, arvind kumar <[email protected]>wrote:
>>
>>> Find the least time complexity algorithm(most efficient algo) to find
>>> x^m(x to the power of m)..Facebok intern interview question!
>>>
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>>
>>
>> --
>> Saurabh Singh
>> B.Tech (Computer Science)
>> MNNIT ALLAHABAD
>>
>>
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>
>
> --
> Ankur Khurana
> Computer Science
> Netaji Subhas Institute Of Technology
> Delhi.
>
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