@amol and saurabh : How exactly is that formula derived for this
problem ?
I need to know the method to evaluate such problems in the future .
Thank you

On Jul 30, 1:13 pm, saurabh singh <[email protected]> wrote:
> Thanx mate.......You rock.:)
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> On Sat, Jul 30, 2011 at 1:40 PM, Amol Sharma <[email protected]> wrote:
> > i think saurabh you wanted to say this --
>
> > x^n=pow(x^n/2)*pow(x^n/2)*(x^(*n*mod2))
> > --
>
> > Amol Sharma
> > Third Year Student
> > Computer Science and Engineering
> > MNNIT Allahabad
>
> > On Sat, Jul 30, 2011 at 1:10 PM, Ankur Khurana 
> > <[email protected]>wrote:
>
> >> use divide and conquer  . logm complexity . . .
>
> >> On Sat, Jul 30, 2011 at 1:09 PM, saurabh singh <[email protected]>wrote:
>
> >>> o(log n)
> >>> x^n=pow(x^n/2)*pow(x^n/2)*(x^mod2)
>
> >>> the base case pow(x,1)=x  pow(x,0)=1
>
> >>> On Sat, Jul 30, 2011 at 1:02 PM, arvind kumar <[email protected]>wrote:
>
> >>>> Find the least time complexity algorithm(most efficient algo) to find
> >>>> x^m(x to the power of m)..Facebok intern interview question!
>
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> >>> --
> >>> Saurabh Singh
> >>> B.Tech (Computer Science)
> >>> MNNIT ALLAHABAD
>
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> >> --
> >> Ankur Khurana
> >> Computer Science
> >> Netaji Subhas Institute Of Technology
> >> Delhi.
>
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> --
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT ALLAHABAD

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