@Dipankar : thanks.............i think,this is the right logic

On Thu, Aug 4, 2011 at 11:10 AM, Dipankar Patro <[email protected]> wrote:

> Well I think the reason is very simple:
> When you enter the loop through L, the value of i is not initialized to 0,
> it is some garbage value.
> now while exiting the loop, the condition is checked for another iteration.
> Since the value of i is unknown, it might be the case that i<j for a lot of
> number of times before the loop actually ends.
>
> But it is not a runtime error, and no infinite loop. the loop will end, the
> moment value of i becomes >= j.
>
> On 4 August 2011 11:00, TUSHAR <[email protected]> wrote:
>
>> #include<stdio.h>
>> main()
>> {
>>              int j=4,i;
>>              goto L;
>>              for(i=0;i<j;i++)
>>              {
>>
>>               L:
>>                         printf("%d",j);
>>               }
>> }
>>
>>
>>
>>
>> why this is giving infinite loop.................Runtime error ?
>>
>>
>>
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>
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-- 
Tushar Kanta Rath,
Master In Computer Application
MNNIT, Allahabad

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