You are welcome Tushar.
My suggestion is always to print the value of iter (i in this case) in a
loop if you think there is something wrong. Helps 99% of times.

On 4 August 2011 20:13, Tushar Kanta Rath <[email protected]>wrote:

> @Dipankar : thanks.............i think,this is the right logic
>
> On Thu, Aug 4, 2011 at 11:10 AM, Dipankar Patro <[email protected]>wrote:
>
>> Well I think the reason is very simple:
>> When you enter the loop through L, the value of i is not initialized to 0,
>> it is some garbage value.
>> now while exiting the loop, the condition is checked for another
>> iteration. Since the value of i is unknown, it might be the case that i<j
>> for a lot of number of times before the loop actually ends.
>>
>> But it is not a runtime error, and no infinite loop. the loop will end,
>> the moment value of i becomes >= j.
>>
>> On 4 August 2011 11:00, TUSHAR <[email protected]> wrote:
>>
>>> #include<stdio.h>
>>> main()
>>> {
>>>              int j=4,i;
>>>              goto L;
>>>              for(i=0;i<j;i++)
>>>              {
>>>
>>>               L:
>>>                         printf("%d",j);
>>>               }
>>> }
>>>
>>>
>>>
>>>
>>> why this is giving infinite loop.................Runtime error ?
>>>
>>>
>>>
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>
>
>
> --
> Tushar Kanta Rath,
> Master In Computer Application
> MNNIT, Allahabad
>
>
>
>
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