There is no difference between the two...

On 32 bit system, both structures need every address location where
int and pointer are stored to be a multiple of 4(highest size is 4)..

On 64 bit,
even if pointer is 4bytes(say, in 64 bit system), and p1, p2 be
structure variables, then p2 should start at address which is multiple
of 8 as int data is 8bytes. So, if p1 starts at 0, it should end at 16
not 12 so that p2 starts at 8's multiple.

This is done by padding pointer by 4bytes in both I and II struct. declarations.


Hope i made it clear...!

Thanks.




On 8/6/11, Tushar Bindal <[email protected]> wrote:
> http://www.serc.iisc.ernet.in/ComputingFacilities/systems/cluster/xlf/html/xlfug/ug35.htm
> this says int is always 4 bytes and pointer is 8 bytes on 64 bit compiler.
>
> so how does padding affect these structures because of the difference in
> size of int and pointer?
>
>
> I tried this program
> https://ideone.com/CRU6x#view_edit_box
> char always gets 4 bytes whenever it has int or double in the same struct
> irrrespctive of the order of the declaration of variables.
> I thought char should get size 8 when there is a double in the ame struct
> whereas it gets size 4 only.
> what is the problem here?
>
> On Sat, Aug 6, 2011 at 4:40 AM, Shashank Jain <[email protected]> wrote:
>
>> i dont understand the diff btw dem, could u plz elaborate?
>>
>> Shashank Jain
>> IIIrd year
>> Computer Engineering
>> Delhi College of Engineering
>>
>>
>>
>> On Sat, Aug 6, 2011 at 12:32 AM, Kamakshii Aggarwal <[email protected]
>> > wrote:
>>
>>> in case of 64 bit,
>>> size of second structure will also be 16 not 8
>>>
>>>
>>> On Fri, Aug 5, 2011 at 11:40 PM, UTKARSH SRIVASTAV <
>>> [email protected]> wrote:
>>>
>>>> I think voth are just same..................
>>>>
>>>>
>>>> On Fri, Aug 5, 2011 at 10:57 AM, priya v <[email protected]> wrote:
>>>>
>>>>> in case of 64 bit machine y doesn't padding happen in the 2nd
>>>>> structure?
>>>>>
>>>>>
>>>>> On Fri, Aug 5, 2011 at 11:21 PM, hary rathor
>>>>> <[email protected]>wrote:
>>>>>
>>>>>> no ,if u r using 32 bit machine . that will use 4 byte pointer size ,
>>>>>> but   in 64 machine that enforce to be size of 8 . where padding will
>>>>>> take int your given first structure
>>>>>>
>>>>>> so for 32 bit- size will 8 8 for both structure
>>>>>> for 64 bit - size will 16 and 12 respectively cause of 4 bit padding
>>>>>> in
>>>>>> one structure
>>>>>>
>>>>>> hence 2nd structure is good for use
>>>>>>
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>>> Kamakshi
>>> [email protected]
>>>
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>
>
>
> --
> Tushar Bindal
> Computer Engineering
> Delhi College of Engineering
> Mob: +919818442705
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