take this case
struct demo
{
char c;
double d;
int s;
> }
what wud be the size??
solution is 24 according to following:-->
char (1) + 7 byte padding +double(8)+int(4)+ 4 byte padding
suppose address starts at 4..
i just wanna ask .. why there is 7 byte padding.. because just after 3 bytes
padding after char we are getting address that is multiple of 8(size of
largest)..
can u please tell me??
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