On Sat, Aug 6, 2011 at 8:24 PM, muthu raj <[email protected]> wrote:
> Microsoft written: > > What is the probability of getting atleast one 6 in 3 attempts of a dice? > > probability of not getting 6 = 5/6 * 5/6 * 5/6 = 91/216 > so ans 1- 91/216 let me know how was the paper and the pattern > *Muthuraj R > IV th Year , ISE > PESIT , Bangalore* > > > > > On Sat, Aug 6, 2011 at 7:34 AM, shady <[email protected]> wrote: > >> Hi, >> >> A fair dice is rolled. Each time the value is noted and running sum is >> maintained. What is the expected number of runs needed so that the sum is >> even ? >> Can anyone tell how to solve this problem ? as well as other related >> problems of such sort.... >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
