Expected value of a random variable x is defined as E(x)= summation of xp(x)
over all value of x where p(x) is the probability.
so in this case
E(x)= E(2)+E(4)+ E(6)+ .....
= 2*1/6 + 4* 3/(6*6)+ 6*10/(6*6*6) + .....
On Sat, Aug 6, 2011 at 9:19 PM, sukran dhawan <[email protected]>wrote:
>
>
> On Sat, Aug 6, 2011 at 8:24 PM, muthu raj <[email protected]> wrote:
>
>> Microsoft written:
>>
>> What is the probability of getting atleast one 6 in 3 attempts of a dice?
>>
>> probability of not getting 6 = 5/6 * 5/6 * 5/6 = 91/216
>>
> so ans 1- 91/216
> let me know how was the paper and the pattern
>
>> *Muthuraj R
>> IV th Year , ISE
>> PESIT , Bangalore*
>>
>>
>>
>>
>> On Sat, Aug 6, 2011 at 7:34 AM, shady <[email protected]> wrote:
>>
>>> Hi,
>>>
>>> A fair dice is rolled. Each time the value is noted and running sum is
>>> maintained. What is the expected number of runs needed so that the sum is
>>> even ?
>>> Can anyone tell how to solve this problem ? as well as other related
>>> problems of such sort....
>>>
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>>
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>
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Regards
Kunal Yadav
(http://algoritmus.in/)
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