@shady: 3/5 can be the answer to such a question: what is prob of getting
head on nth toss if we have 4 coins fair and one biased...then at nth toss u
choose 4/5 1/5 prob and then u get 3/5

@shady , don: i did this: P( 6th head | 5 heads occured)= P( 6 heads )/ P( 5
heads)

answr u get is 17/18..i cud be wrong please correct if so

On Mon, Aug 8, 2011 at 10:45 PM, shady <[email protected]> wrote:

> answer is 3/5. 17/80 is the answer for 6 consecutive heads.
>
>
> On Tue, Aug 9, 2011 at 2:07 AM, Don <[email protected]> wrote:
>
>> Consider the 5 * 64 possible outcomes for the selection of coin and
>> six flips, each one happening with equal probability. Of those 320
>> possible outcomes, 4*62 are excluded by knowing that the first 5 flips
>> are heads. That leaves 64 outcomes with the rigged coin and 2 outcomes
>> with each of the fair coins, for a total of 72 outcomes. 68 of those
>> are heads, so the answer to the puzzle is 68 of 72, or 17 of 18.
>> Don
>>
>> On Aug 8, 2:36 am, Shachindra A C <[email protected]> wrote:
>> > @brijesh
>> >
>> > *first five times* is mentioned intentionally to mislead i think. I vote
>> for
>> > 3/5. Moreover, 17/80 doesn't make sense also. Plz correct me if I am
>> wrong.
>> >
>> >
>> >
>> > On Mon, Aug 8, 2011 at 12:06 PM, sumit gaur <[email protected]>
>> wrote:
>> > > (3/5)
>> >
>> > > On Aug 7, 10:34 pm, Algo Lover <[email protected]> wrote:
>> > > > A bag contains 5 coins. Four of them are fair and one has heads on
>> > > > both sides. You randomly pulled one coin from the bag and tossed it
>> 5
>> > > > times, heads turned up all five times. What is the probability that
>> > > > you toss next time, heads turns up. (All this time you don't know
>> you
>> > > > were tossing a fair coin or not).
>> >
>> > > --
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>> > --
>> > Regards,
>> > Shachindra A C
>>
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