sorry that was for equal case : for unequal case 1-(73/648)= 575/648
On Fri, Aug 12, 2011 at 2:28 AM, Prakash D <[email protected]> wrote:
> total possible outcomes= 6*6*6*6
>
> possibility of sum gives 2 in both pair --> 1*1*1*1 =1
> possibility of sum gives 3 in both pair --> 2*1*2*1 =4
> {because the possibilities are (1,2)(1,2), (1,2)(2,1), (2,1)(1,2),
> (2,1)(2,1)}
> possibility of 4 --> 9 { 2,2 1,3 and 3,1}
> possibility of 5 --> 16 {1,4 2,3 3,2 4,1}
> possibility of 6 --> 25 {1,5 2,4 3,3 4,2 5,1}
> possibility of 7 --> 36 {1,6 2,5 3,4 4,3 5,2 6,1}
> possibility of 8 --> 25 {2,6 3,5 4,4 5,3 6,2}
> 9--> 16
> 10 --> 9
> 11 --> 4
> 12 --> 1
>
> so probability required = (1+4+9+16+25+36+25+16+9+4+1)/(6*6*6*6)
> =146/1296
> =73/648
>
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