it can be done in O(3n). in worst case one row will have max and anothr row will have min so the third row will be your o/p to print
On Mon, Aug 15, 2011 at 12:00 AM, Karthikeyan palani < [email protected]> wrote: > sorry O(n^2) s the time complexity > > > On 14 August 2011 23:56, shady <[email protected]> wrote: > >> how can it be O(n) when there are itself n*n elements.. >> >> PS : no sharing of code, else the inevitable >> >> On Sun, Aug 14, 2011 at 11:51 PM, Karthikeyan palani < >> [email protected]> wrote: >> >>> Given a n x n matrix. .number are randomly placed. .print any one row >>> which doesn’t have min >>> and max elements. Time Complexity : 0(n) >>> >>> >>> >>> if anyone know the code.. pls share!!! >>> >>> -- >>> karthikeyankkn >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to [email protected]. >>> To unsubscribe from this group, send email to >>> [email protected]. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > karthikeyankkn > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
