yes

On Mon, Aug 15, 2011 at 12:58 AM, aditi garg <[email protected]>wrote:

> @shady : does O(3n) include the time required to find the max and min
> element as well??
>
>
> On Mon, Aug 15, 2011 at 12:50 AM, shady <[email protected]> wrote:
>
>> no it is 3*n only........ read it again
>>
>>
>> On Mon, Aug 15, 2011 at 12:45 AM, Amir Aavani <[email protected]>wrote:
>>
>>>
>>> On 08/14/2011 11:46 AM, aditya kumar wrote:
>>>
>>>> it can be done in O(3n). in worst case one row will have max and anothr
>>>> row
>>>> will have min so the third row will be your o/p to print
>>>>
>>> Do you mean O(n^3)?
>>>
>>> Consider this { O(n^2) }:
>>>
>>>  1- Scan the whole matrix and find minimum and maximum entries in the
>>> matrix. Let Delta be the difference between maximum and minimum.
>>>  2- For each row, find the minimum and maximum entries in that row. If
>>> their difference is exactly Delta, then print that row.
>>>
>>>
>>> Amir
>>>
>>>
>>>
>>>> On Mon, Aug 15, 2011 at 12:00 AM, Karthikeyan palani<
>>>> [email protected]>  wrote:
>>>>
>>>>  sorry O(n^2) s the time complexity
>>>>>
>>>>>
>>>>> On 14 August 2011 23:56, shady<[email protected]>  wrote:
>>>>>
>>>>>  how can it be O(n) when there are itself n*n elements..
>>>>>>
>>>>>> PS : no sharing of code, else the inevitable
>>>>>>
>>>>>> On Sun, Aug 14, 2011 at 11:51 PM, Karthikeyan palani<
>>>>>> [email protected]>  wrote:
>>>>>>
>>>>>>  Given a n x n matrix. .number are randomly placed. .print any one row
>>>>>>> which doesn’t have min
>>>>>>> and max elements. Time Complexity : 0(n)
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> if anyone know the code.. pls share!!!
>>>>>>>
>>>>>>> --
>>>>>>> karthikeyankkn
>>>>>>>
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>
>
>
> --
> Aditi Garg
> Undergraduate Student
> Electronics & Communication Divison
> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
> Sector 3, Dwarka
> New Delhi
>
>
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