it will work only if all numbers are unique

On Mon, Aug 15, 2011 at 10:50 AM, Ankur Khurana <[email protected]>wrote:

> @shady : what if all the rows hai one min and one max element , which is
> re occurring. your algo doesn't check that
>
> On Mon, Aug 15, 2011 at 1:37 AM, aditya kumar <
> [email protected]> wrote:
>
>> @all: it will take O(3n)  for finding max n min and if and only if all
>> elements in an array are distinct .
>>
>> On Mon, Aug 15, 2011 at 1:30 AM, siddharth srivastava <
>> [email protected]> wrote:
>>
>>>
>>> One approach could be:
>>>
>>> I think the min and max elements can be found in n*n*(3n/2)
>>> keep a flag(or array of flag--bitvector ??) for the rows in which min or
>>> max was found
>>> print all other rows for which flag is not set
>>>
>>> another n^3(confirm please) algo could be:
>>> sort each row individually
>>> compare first col for min, last col for max
>>> print all which do not have min or max
>>>
>>>
>>>
>>>
>>> On 15 August 2011 01:20, shady <[email protected]> wrote:
>>>
>>>> according to me it would be take 4*n time.... 3 iterations to choose the
>>>> min. and max. from 1st three rows, and n again to print the chosen one
>>>>
>>>>
>>>> On Mon, Aug 15, 2011 at 1:13 AM, aditi garg 
>>>> <[email protected]>wrote:
>>>>
>>>>> some how im not able to get the logic...how will i be able to find max
>>>>> and min of the entire matrix by jst traversing 3 rows??
>>>>>
>>>>> for eg
>>>>>  1 2 3 4 5
>>>>>  8 1 3 6 9
>>>>> 4 6 3 2 10
>>>>> 9 0 5 8 12
>>>>> 18 2 6 7 3
>>>>> fr dis matrix how will u find max and min??
>>>>>
>>>>>
>>>>> On Mon, Aug 15, 2011 at 1:04 AM, aditya kumar <
>>>>> [email protected]> wrote:
>>>>>
>>>>>> just traverse the three rows and get the max and min out of the three
>>>>>> rows . print the row in which their is no max and min .
>>>>>>
>>>>>>
>>>>>> On Mon, Aug 15, 2011 at 1:02 AM, aditya kumar <
>>>>>> [email protected]> wrote:
>>>>>>
>>>>>>> yes
>>>>>>>
>>>>>>>
>>>>>>> On Mon, Aug 15, 2011 at 12:58 AM, aditi garg <
>>>>>>> [email protected]> wrote:
>>>>>>>
>>>>>>>> @shady : does O(3n) include the time required to find the max and
>>>>>>>> min element as well??
>>>>>>>>
>>>>>>>>
>>>>>>>> On Mon, Aug 15, 2011 at 12:50 AM, shady <[email protected]> wrote:
>>>>>>>>
>>>>>>>>> no it is 3*n only........ read it again
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> On Mon, Aug 15, 2011 at 12:45 AM, Amir Aavani <
>>>>>>>>> [email protected]> wrote:
>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> On 08/14/2011 11:46 AM, aditya kumar wrote:
>>>>>>>>>>
>>>>>>>>>>> it can be done in O(3n). in worst case one row will have max and
>>>>>>>>>>> anothr row
>>>>>>>>>>> will have min so the third row will be your o/p to print
>>>>>>>>>>>
>>>>>>>>>> Do you mean O(n^3)?
>>>>>>>>>>
>>>>>>>>>> Consider this { O(n^2) }:
>>>>>>>>>>
>>>>>>>>>>  1- Scan the whole matrix and find minimum and maximum entries in
>>>>>>>>>> the matrix. Let Delta be the difference between maximum and minimum.
>>>>>>>>>>  2- For each row, find the minimum and maximum entries in that
>>>>>>>>>> row. If their difference is exactly Delta, then print that row.
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> Amir
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>> On Mon, Aug 15, 2011 at 12:00 AM, Karthikeyan palani<
>>>>>>>>>>> [email protected]>  wrote:
>>>>>>>>>>>
>>>>>>>>>>>  sorry O(n^2) s the time complexity
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> On 14 August 2011 23:56, shady<[email protected]>  wrote:
>>>>>>>>>>>>
>>>>>>>>>>>>  how can it be O(n) when there are itself n*n elements..
>>>>>>>>>>>>>
>>>>>>>>>>>>> PS : no sharing of code, else the inevitable
>>>>>>>>>>>>>
>>>>>>>>>>>>> On Sun, Aug 14, 2011 at 11:51 PM, Karthikeyan palani<
>>>>>>>>>>>>> [email protected]>  wrote:
>>>>>>>>>>>>>
>>>>>>>>>>>>>  Given a n x n matrix. .number are randomly placed. .print any
>>>>>>>>>>>>>> one row
>>>>>>>>>>>>>> which doesn’t have min
>>>>>>>>>>>>>> and max elements. Time Complexity : 0(n)
>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> if anyone know the code.. pls share!!!
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> --
>>>>>>>>>>>>>> karthikeyankkn
>>>>>>>>>>>>>>
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>>>>>>>>
>>>>>>>>
>>>>>>>> --
>>>>>>>> Aditi Garg
>>>>>>>> Undergraduate Student
>>>>>>>> Electronics & Communication Divison
>>>>>>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>>>>>>> Sector 3, Dwarka
>>>>>>>> New Delhi
>>>>>>>>
>>>>>>>>
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>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Aditi Garg
>>>>> Undergraduate Student
>>>>> Electronics & Communication Divison
>>>>> NETAJI SUBHAS INSTITUTE OF TECHNOLOGY
>>>>> Sector 3, Dwarka
>>>>> New Delhi
>>>>>
>>>>>
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>>>
>>>
>>>
>>> --
>>> Regards
>>> Siddharth Srivastava
>>>
>>>
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>
>
>
> --
> Ankur Khurana
> Computer Science
> Netaji Subhas Institute Of Technology
> Delhi.
>
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