if the cyclist would have left on time, then in those 20 minutes, he would have covered 4miles at a speed of 12miles/h so he would have been 1 mile before station whereas train would have been 5 miles before as it is on its normal time, so no change in its position. then, when the cyclist covers that 1 mile, the train covers 5 miles so that both of them meet at the station. thus, speed of the train = 5*speed of cyclist = 60 miles/hour
On Sun, Aug 21, 2011 at 12:19 PM, prasanth n <[email protected]> wrote: > @gupta: > > can you explain your answer? > > > On Sun, Aug 21, 2011 at 1:50 AM, D!leep Gupta <[email protected]>wrote: > >> 60mph >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > *prasanth* > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Tushar Bindal Computer Engineering Delhi College of Engineering Mob: +919818442705 E-Mail : [email protected] Website: www.jugadengg.com -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
