It would be sum of number of  factors of both the numbers.
24 -1,2,3,4,6,8,12,24
33-1,3,11,33


On Tue, Aug 23, 2011 at 10:54 PM, Aman Goyal <[email protected]> wrote:

> ans is 12, but instead of counting i am looking for some better solution.
>
>
> On Tue, Aug 23, 2011 at 10:48 PM, manish patel <[email protected]>wrote:
>
>>
>> (24,33),(12,66),(8,99),(6,132),(4,198),(3,254),(2,396),(1,792),(792,1),(72,11),(264,3),(33,24)
>>
>> On Tue, Aug 23, 2011 at 10:18 PM, Aman Goyal <[email protected]>wrote:
>>
>>> Let a natural number N be such that N = a × b where a and b are the
>>> factors of N. How many such sets of (a, b) can be formed in which the
>>> selection of the two numbers a and b is distinctly different if N = 24 × 33?
>>>
>>> Please explain your solution also.
>>>
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>>
>>
>>
>> --
>> With Regards
>>
>> Manish Patel
>> BTech 3rd Year
>> Computer Science And Engineering
>> National Institute of Technology -Allahabad
>>
>>
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