How about this answer:
b?z:y
int main() {
int a=0,b,y=4,z=5,k;
cin>>b;
k=(((b+~a+1)>>7)&1);//k will either be 0 or 1
cout<< (z-int((bool)k&(z-y)));
return 0;
}
On Mon, Sep 12, 2011 at 5:32 PM, beginner <[email protected]> wrote:
> although multiplication operator is not allowed..
> but it's an attempt to write shorter...
>
> c++ implementation-
>
> int cond(int x, int y, int z){
> return y*(int)((bool)x)+z*(1+(~(int)((bool)x)+1));
>
> }
>
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Regards
Ravi Maggon
B.E. CSE, Final Year
Thapar University
www.algorithmguru.com
"*Failure is the opportunity to begin again more intelligently"*
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