return (((-1+!x)&y) | ((-1+!!x)&z)) ;

On Sun, Oct 2, 2011 at 3:18 PM, ravi maggon <[email protected]> wrote:
> How about this answer:
> b?z:y
>
> int main() {
>     int a=0,b,y=4,z=5,k;
>     cin>>b;
>     k=(((b+~a+1)>>7)&1);//k will either be 0 or 1
>     cout<< (z-int((bool)k&(z-y)));
>     return 0;
> }
>
> On Mon, Sep 12, 2011 at 5:32 PM, beginner <[email protected]> wrote:
>>
>> although multiplication operator is not allowed..
>> but it's an attempt to write shorter...
>>
>> c++ implementation-
>>
>> int cond(int x, int y, int z){
>>      return  y*(int)((bool)x)+z*(1+(~(int)((bool)x)+1));
>> }
>>
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>
>
>
> --
> Regards
> Ravi Maggon
> B.E. CSE, Final Year
> Thapar University
>
> www.algorithmguru.com
>
> "Failure is the opportunity to begin again more intelligently"
>
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>



-- 
Varun Jakhoria
...it's only about 0's & 1's

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