wont work......Thre is no way compilers gonna guess which function to call.The const qualifier only guarantees that the value at the address wont be altered inside the function.That has nothing to do with calling,
On Sun, Nov 20, 2011 at 9:50 PM, rahul vatsa <[email protected]> wrote: > yes, it will work. > > > On Sun, Nov 20, 2011 at 9:12 PM, Akash Coder > <[email protected]>wrote: > >> no it wont work ... const is not a datatype. its a qualifier >> >> >> On Sun, Nov 20, 2011 at 7:49 PM, rahul sharma <[email protected]>wrote: >> >>> void fun(char *) >>> void fun(const char *) >>> >>> >>> >>> is this overloading works or these are same type of arguments?????? >>> >>> -- >>> You received this message because you are subscribed to the Google >>> Groups "Algorithm Geeks" group. >>> To post to this group, send email to [email protected]. >>> To unsubscribe from this group, send email to >>> [email protected]. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Saurabh Singh B.Tech (Computer Science) MNNIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
