this is what i am getting after executing code meintion in the above link.

(using gcc compiler )

temp.c:12: error: conflicting types for 'fun'
temp.c:7: error: previous definition of 'fun' was here


On Mon, Nov 21, 2011 at 3:09 PM, UTKARSH SRIVASTAV
<[email protected]>wrote:

> http://www.ideone.com/JQFNh
> CHECK THE OUTPUT THERE IS NO AMBIGUITY BUT PLEASE EXPLAIN THE RESULTS
>
>
> On Sun, Nov 20, 2011 at 11:00 PM, Akash Coder 
> <[email protected]>wrote:
>
>> it wont work
>>
>> even this wont
>>
>> function(char a[])
>> function (char *)
>> coz the two forms are interchangeable
>>
>>
>> On Sun, Nov 20, 2011 at 10:12 PM, saurabh singh <[email protected]>wrote:
>>
>>> wont work......Thre is no way compilers gonna guess which function to
>>> call.The const qualifier only guarantees that the value at the address wont
>>> be altered inside the function.That has nothing to do with calling,
>>>
>>>
>>> On Sun, Nov 20, 2011 at 9:50 PM, rahul vatsa <[email protected]>wrote:
>>>
>>>> yes, it will work.
>>>>
>>>>
>>>> On Sun, Nov 20, 2011 at 9:12 PM, Akash Coder <
>>>> [email protected]> wrote:
>>>>
>>>>> no it wont work ... const is not a datatype. its  a qualifier
>>>>>
>>>>>
>>>>> On Sun, Nov 20, 2011 at 7:49 PM, rahul sharma <[email protected]
>>>>> > wrote:
>>>>>
>>>>>> void fun(char *)
>>>>>> void fun(const char *)
>>>>>>
>>>>>>
>>>>>>
>>>>>> is this overloading works or these are same type of arguments??????
>>>>>>
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>>>
>>>
>>>
>>> --
>>> Saurabh Singh
>>> B.Tech (Computer Science)
>>> MNNIT ALLAHABAD
>>>
>>>
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>
>
> --
> *UTKARSH SRIVASTAV
> CSE-3
> B-Tech 3rd Year
> @MNNIT ALLAHABAD*
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