At first the value of a is calculated for the statement, that is 6, and
then statement is evaluated with a=6
so it is 6 + 6 + 6 = 18
and as you know after that the value of a becomes 7 for the rest of the
program.

On Mon, May 28, 2012 at 10:02 AM, ashish pant <[email protected]> wrote:

> #include<stdio.h>
> int main()
> {
>           int a=4;
>           printf("%d\n",++a + ++a + a++);
>           return 0;
> }
>
> according to me output should be 17, but it is coming out to be 18.
> plz explain it??
>
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-- 
   MeHdi KaZemI

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