It's output will be compiler dependent.
So on Turbo C, compiler will perform all pre-increment operation first then
will start adding.
like in your problem all "++a" operation will go first. then addition will
happen.
so 6+6+6=18.
on gcc, first two variables will it take, performs pre-increment operation
and then adding and then third variable will come.as it continues.
As in this case in gcc it will be performed like,
(++a + ++a) + (a++)=(6+6)+6=18
post-increment will be unaffected during entire expression.
Feel free to ask if you didn't got what i explained.
On Monday, May 28, 2012 11:02:03 AM UTC+5:30, ashish wrote:
>
> #include<stdio.h>
> int main()
> {
> int a=4;
> printf("%d\n",++a + ++a + a++);
> return 0;
> }
>
> according to me output should be 17, but it is coming out to be 18.
> plz explain it??
>
>
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