oh ,now i see. 300 = 0000000100101100
first 8 bits = 00000001
last 8 bits = 00101100

in case of big-endian machine, when we assign 2 to next location, last 8
bits become 00000010 (2 in decimal), first 8 bits remain same.
in case of little-endian machine, when we assign 2 to next location, last 8
bits become 00000010 (2 in decimal), last 8 bits remain same.

Am i right ?

On Thu, Jun 7, 2012 at 12:53 PM, Abhishek Sharma <[email protected]>wrote:

> @prem, i don't get it.could you please elaborate the interesting part of
> this solution ?
>
>
> On Thu, Jun 7, 2012 at 11:39 AM, Abhishek Sharma <[email protected]>wrote:
>
>> Is there any online compiler which gives output for both little/big
>> endian machines ?
>> or it is fine to convert value from one form to another using a small c
>> program ?
>>
>> On Thu, Jun 7, 2012 at 1:13 AM, Garima Mishra <[email protected]>wrote:
>>
>>> 556 if the machine is little endian
>>> 258 if machine is big endian
>>>
>>> On Jun 6, 11:57 pm, g4ur4v <[email protected]> wrote:
>>> > main()
>>> > {
>>> > int i=300;
>>> > char *ptr = &i;
>>> > *++ptr=2;
>>> > printf("%d",i);
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> > }
>>>
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>>>
>>
>>
>> --
>> Abhishek Sharma
>> Under-Graduate Student,
>> PEC University of Technology
>>
>>
>
>
> --
> Abhishek Sharma
> Under-Graduate Student,
> PEC University of Technology
>
>


-- 
Abhishek Sharma
Under-Graduate Student,
PEC University of Technology

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