@Abhishek : correct ....

On Thu, Jun 7, 2012 at 1:03 PM, Abhishek Sharma <[email protected]>wrote:

> oh ,now i see. 300 = 0000000100101100
> first 8 bits = 00000001
> last 8 bits = 00101100
>
> in case of big-endian machine, when we assign 2 to next location, last 8
> bits become 00000010 (2 in decimal), first 8 bits remain same.
> in case of little-endian machine, when we assign 2 to next location, last
> 8 bits become 00000010 (2 in decimal), last 8 bits remain same.
>
> Am i right ?
>
> On Thu, Jun 7, 2012 at 12:53 PM, Abhishek Sharma <[email protected]>wrote:
>
>> @prem, i don't get it.could you please elaborate the interesting part of
>> this solution ?
>>
>>
>> On Thu, Jun 7, 2012 at 11:39 AM, Abhishek Sharma <[email protected]>wrote:
>>
>>> Is there any online compiler which gives output for both little/big
>>> endian machines ?
>>> or it is fine to convert value from one form to another using a small c
>>> program ?
>>>
>>> On Thu, Jun 7, 2012 at 1:13 AM, Garima Mishra <[email protected]>wrote:
>>>
>>>> 556 if the machine is little endian
>>>> 258 if machine is big endian
>>>>
>>>> On Jun 6, 11:57 pm, g4ur4v <[email protected]> wrote:
>>>> > main()
>>>> > {
>>>> > int i=300;
>>>> > char *ptr = &i;
>>>> > *++ptr=2;
>>>> > printf("%d",i);
>>>> >
>>>> >
>>>> >
>>>> >
>>>> >
>>>> >
>>>> >
>>>> > }
>>>>
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>>>>
>>>
>>>
>>> --
>>> Abhishek Sharma
>>> Under-Graduate Student,
>>> PEC University of Technology
>>>
>>>
>>
>>
>> --
>> Abhishek Sharma
>> Under-Graduate Student,
>> PEC University of Technology
>>
>>
>
>
> --
> Abhishek Sharma
> Under-Graduate Student,
> PEC University of Technology
>
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