Clear some more questiosn 1. What is size of reference.????
2.what is return by reference???it means we return the object itself instead of copying it into temp. variable and then return as in c. in c++ we return original variable itself..then when we return by reference wat does that mean,,,does it mean some pointer returned or it mean whole object returned?? On Wed, Oct 10, 2012 at 2:23 AM, rahul sharma <rahul23111...@gmail.com>wrote: > Got confused....cant get it......:([?] > > > On Wed, Oct 10, 2012 at 1:00 AM, Prem Krishna Chettri > <hprem...@gmail.com>wrote: > >> Well Lemme try few more hand here.. >> >> Basics First Guys :- >> >> this :- is a hidden pointer to a class (Agree ?). So whats >> so special about it.. Answer is its compaction when the object of the class >> is being created. Why? Here it goes. As object memory allocation (I hope >> everyone knows) have memory structure such that the first parameter always >> starts with arg[1]. so why not arg[0] as array always indexes with "0"? The >> Answer is here.. Coz every time the object of a class is generated the >> Zeroth index is alwayz occupied by this "*this*" pointer. So if do you >> follow me up to here properly that you know the significance of this now.. >> Coz its object refference lies to the value of offset 0 to the base address >> of the class's object, giving the flexibility to express any member of the >> class by directly accessing via its base address and this also explains why >> this has to be a pointer and not a normal member variable. >> >> Now here comes the other part of question.why we need *" * >> * *this"* where *"this"* should give the base address of the object of >> the class we wanna refer. The Answer is partly "YES" coz as we discuss >> "*this" >> *knows almost everything about the class or rather an object of a class >> within a class scope but here is the catch we are telling someone to get a >> bowl of rice from my private house. So how will he be able to get it? Until >> I tell him my house structure, which in programming language like C++ is >> reference. >> >> I am saying sir, I have created a house (object) and here is >> the layout (referring to what I have created) so inorder to tell him about >> my layout I have to generate the return value which is NOT the house >> (object) but the reference to the house ( "pointer" pointing to what I have >> created ). >> >> Now I am almost done here.. So Why " ** this *" and not "*this*" >> is coz "*this"* gives the object directly to the the party who is >> calling me and the reference means a copy not the object itself whereas " >> ** this *" is presenting you what you were looking for. >> >> I hope now people are clear about all the above aspects.. I mean >> the very last question about returns full object or wat?? if you get all >> this.. U got all this.. :) >> >> Ciao, >> Prem >> >> >> >> >> >> >> On Wed, Oct 10, 2012 at 12:23 AM, rahul sharma >> <rahul23111...@gmail.com>wrote: >> >>> @saurabh....if i look from the way that i need to return a referencei.e. >>> i mean object...i will ryt *this for this..........i knew >>> this............but i have read that reference is a const pointer ....so if >>> i look from this prespective then do i need to return >>> pointer(this).............. >>> int * fun()//return pointer to int >>> >>> then what does return by reference mean if i return ( *this)..then what >>> actually returns...........full object???or pointer to object...mix >>> questions ...plz clear me.. >>> >>> >>> On Tue, Oct 9, 2012 at 11:26 PM, Saurabh Kumar <srbh.ku...@gmail.com>wrote: >>> >>>> >> as we know reference is a const pointer >>>> That is Not quite true. >>>> >>>> >> our aim is ony to return pointer to circle >>>> No. our aim is to return a reference to circle. >>>> >>>> When you've to define a reference you do something like: *Circle &ref >>>> = c;* >>>> you *don't* do: *Circle &ref = &c;* Right ? >>>> >>>> Same is the case here, at the receiving end where the call was >>>> initiated a reference is waiting there to be initialized, so you pass the >>>> Object (*this) itself and NOT the pointer (this). >>>> [Also remember if you've a complex object, no copy constructors etc. >>>> are called when an object is sent for *reference receiving,* so no >>>> need of worries there.] >>>> >>>> References are not quite exactly same as pointers, they were introduced >>>> much later as a wrapper to pointers but there are some subtle differences >>>> between them when it comes to writing code, behaviorally, yes they are more >>>> or less the same. >>>> >>>> On 9 October 2012 22:54, SAMM <somnath.nit...@gmail.com> wrote: >>>> >>>>> This used for the following situation when a=b=c=d (Consider then >>>>> as the objects of a particular class say X ). >>>>> >>>>> >>>>> -- >>>>> You received this message because you are subscribed to the Google >>>>> Groups "Algorithm Geeks" group. >>>>> To post to this group, send email to algogeeks@googlegroups.com. >>>>> To unsubscribe from this group, send email to >>>>> algogeeks+unsubscr...@googlegroups.com. >>>>> For more options, visit this group at >>>>> http://groups.google.com/group/algogeeks?hl=en. >>>>> >>>> >>>> -- >>>> You received this message because you are subscribed to the Google >>>> Groups "Algorithm Geeks" group. >>>> To post to this group, send email to algogeeks@googlegroups.com. >>>> To unsubscribe from this group, send email to >>>> algogeeks+unsubscr...@googlegroups.com. >>>> For more options, visit this group at >>>> http://groups.google.com/group/algogeeks?hl=en. >>>> >>> >>> -- >>> You received this message because you are subscribed to the Google >>> Groups "Algorithm Geeks" group. >>> To post to this group, send email to algogeeks@googlegroups.com. >>> To unsubscribe from this group, send email to >>> algogeeks+unsubscr...@googlegroups.com. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. 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