Gary, Mike,

> I should rephrase that. The score that is reported in the header (and
> the log) is not correct for messages that are quarantined. Amavisd-new
> still does the right thing as far as where the message should go.
> This may also explain what happened in this thread:
> "Below taglevel but still beeing caught?!"
> http://marc.theaimsgroup.com/?l=amavis-user&m=112042284601591&w=2

| This makes more sense now.  The additional 5 score from amavis' AWL added to
| the existing SA score indeed brings the message above the kill2 level.
|
| So, I agree we have a bug / feature request here.
|
| Mark M. - Any chance of updating the scores output on non-passed messages
| such that they reflect the true value used in determining the message's
| disposition?

The sender_score is a per-recipient thing. The locations where only
per-message information is reported do not necessarily represent things
accurately, e.g. if one recipient blacklists a mail and the other not,
is the message blacklisted or not?  Similarly for the final score, which
is a sum of per-message score as reported by SA, plus the per-recipient
score_sender boost.

The main log entry with 2.3.2 now reports hits as an explicit sum of
SA score and sender score to make it more obvious.

The quarantined message only contains one set of X-Spam and other inserted
headers, even when the message was addressed to more than one recipient
and their settings (e.g. kill level) were different. To reflect the truth, 
there should either be several quarantined copies, one for each recipient,
or there should be perhaps multiple instances of X-Spam* headers, one set
for each recipient. At the moment this is not so, the information is 'somehow'
aggregated into a per-message set of headers, with a necessary loss of
information, such a per-recipient score-sender boosts.

The main log entry and the passed message are accurate though, and so is the
SQL report/log, which has a spam score sum in per-recipient table.

The problem is noted in TODO, but I don't know what the best solution
would be.

  Mark


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