Sorry... let me repost that code...
HLRange = abs( H - L );
ABC = HLRange > Ref( HLRange, -1 ) AND HLRange > Ref( HLRange, -2) AND
HLRange > Ref( HLRange, -3 );
XYZ_Check=IIf(Ref(ABC,-1),1,IIf(Ref(ABC,-2),2,IIf(Ref(ABC,-3),3,0)));
if(XYZ_Check==0)
{
printf("XYZ_Check = " + XYZ_Check);
}
if(XYZ_Check==1)
{
printf("XYZ_Check = " + XYZ_Check);
}
if(XYZ_Check==2)
{
printf("XYZ_Check = " + XYZ_Check);
}
if(XYZ_Check==3)
{
printf("XYZ_Check = " + XYZ_Check);
}
--- In [email protected], "sidhartha70" <[EMAIL PROTECTED]> wrote:
>
> Hi All,
>
> I keep running into a consistent coding structure problem,
>
> HLRange = abs( H - L );
> ABC = HLRange > Ref( HLRange, -1 ) AND HLRange > Ref( HLRange, -2 )
> AND HLRange > Ref( HLRange, -3 );
> XYZ_Check=IIf(Ref(ABC,-1),1,IIf(Ref(ABC,-2),2,IIf(Ref(ABC,-3),3,0)));
>
> if(ABC_Check==0)
> {
> printf("ABC_Check = " + ABC_Check);
> }
> if(ABC_Check==1)
> {
> printf("ABC_Check = " + ABC_Check);
> }
> if(ABC_Check==2)
> {
> printf("ABC_Check = " + ABC_Check);
> }
> if(ABC_Check==3)
> {
> printf("ABC_Check = " + ABC_Check);
> }
>
> Obviously I keep getting Error 6 stating that in the 'if(expression)'
> statements expression cannot be an array.
> This raises a more generic question... is there a way of programming
> structures like these WITHOUT having to resort to using loops....?
>
> Any ideas appreciated.
>
> TIA
>
