The only error I got was "ABC_check" was not initialized. After fixing
that, it ran without error.
On Thu, Nov 6, 2008 at 12:44 PM, sidhartha70 <[EMAIL PROTECTED]> wrote:
> Sorry... let me repost that code...
>
> HLRange = abs( H - L );
> ABC = HLRange > Ref( HLRange, -1 ) AND HLRange > Ref( HLRange, -2) AND
> HLRange > Ref( HLRange, -3 );
> XYZ_Check=IIf(Ref(ABC,-1),1,IIf(Ref(ABC,-2),2,IIf(Ref(ABC,-3),3,0)));
>
> if(XYZ_Check==0)
> {
> printf("XYZ_Check = " + XYZ_Check);
> }
> if(XYZ_Check==1)
> {
> printf("XYZ_Check = " + XYZ_Check);
> }
> if(XYZ_Check==2)
> {
> printf("XYZ_Check = " + XYZ_Check);
> }
> if(XYZ_Check==3)
> {
> printf("XYZ_Check = " + XYZ_Check);
> }
>
> --- In [email protected] <amibroker%40yahoogroups.com>,
> "sidhartha70" <[EMAIL PROTECTED]> wrote:
> >
> > Hi All,
> >
> > I keep running into a consistent coding structure problem,
> >
> > HLRange = abs( H - L );
> > ABC = HLRange > Ref( HLRange, -1 ) AND HLRange > Ref( HLRange, -2 )
> > AND HLRange > Ref( HLRange, -3 );
> > XYZ_Check=IIf(Ref(ABC,-1),1,IIf(Ref(ABC,-2),2,IIf(Ref(ABC,-3),3,0)));
> >
> > if(ABC_Check==0)
> > {
> > printf("ABC_Check = " + ABC_Check);
> > }
> > if(ABC_Check==1)
> > {
> > printf("ABC_Check = " + ABC_Check);
> > }
> > if(ABC_Check==2)
> > {
> > printf("ABC_Check = " + ABC_Check);
> > }
> > if(ABC_Check==3)
> > {
> > printf("ABC_Check = " + ABC_Check);
> > }
> >
> > Obviously I keep getting Error 6 stating that in the 'if(expression)'
> > statements expression cannot be an array.
> > This raises a more generic question... is there a way of programming
> > structures like these WITHOUT having to resort to using loops....?
> >
> > Any ideas appreciated.
> >
> > TIA
> >
>
>
>
