(Also, even caring about the historical data is rare.  If all you need is
the most recent positions, just ignore the historical data.)

On Fri, Oct 15, 2010 at 3:54 PM, Dianne Hackborn <[email protected]>wrote:

> Just think of this as a two dimensional array.  A MotionEvent contains N
> pointers.  That MotionEvent may also have M historical positions each
> containing another N pointers that exactly match the identifiers of the most
> recent pointers in the event.
>
>
> On Fri, Oct 15, 2010 at 2:42 PM, Julio Suarez <[email protected]> wrote:
>
>> Hi,
>>
>> Have you figured this out yet? I too am very confused as to how to
>> handle Historical points when more the one pointer is on the screen. I
>> have no idea how to separate what and how much historical data goes
>> with each pointer.
>>
>> On Aug 22, 6:23 pm, sztupy <[email protected]> wrote:
>> > I couldn't find a definite reference for the size of a MotionEvents
>> > history, when there are multiple pointers. The reference says that if
>> > you use a getHistorical* function, you might pass it a history
>> > position which is somewhere between [0..getHistorySize()-1]. But in a
>> > lot of examples handlingmultitouchif there are multiple pointers
>> > they only use history positions between [0..getHistorySize()/
>> > getPointers()-1] (so they divide the history's size with the number of
>> > pointers). Which one is the correct way?
>> >
>> >  SztupY
>>
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>
>
>
> --
> Dianne Hackborn
> Android framework engineer
> [email protected]
>
> Note: please don't send private questions to me, as I don't have time to
> provide private support, and so won't reply to such e-mails.  All such
> questions should be posted on public forums, where I and others can see and
> answer them.
>
>


-- 
Dianne Hackborn
Android framework engineer
[email protected]

Note: please don't send private questions to me, as I don't have time to
provide private support, and so won't reply to such e-mails.  All such
questions should be posted on public forums, where I and others can see and
answer them.

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