Good question; I'll have to check later, but I know index was 0. On Friday, March 9, 2012 3:27:08 PM UTC-5, MagouyaWare wrote: > > What is the value of "index - getListView().getFirstVisiblePosition()"? > > Thanks, > Justin Anderson > MagouyaWare Developer > http://sites.google.com/site/magouyaware > > > On Fri, Mar 9, 2012 at 1:21 PM, RedBullet <> wrote: > >> OK, so here is my code snipet: >> >> RouteAdapter adapter = new RouteAdapter(this, route.getCues()); >> setListAdapter(adapter); >> setSelection(); >> } >> >> public void setSelection() >> { >> RouteAdapter adapter = (RouteAdapter) getListAdapter(); >> Integer index = adapter.getPosition(nextCuePoint); >> View itemView = this.getListView().getChildAt(index - >> getListView().getFirstVisiblePosition()); >> >> The position of the nextCuePoint is 0 (which is correct since it is the >> first cue). But I am getting null for itemView... >> >> >> On Friday, March 9, 2012 3:11:21 PM UTC-5, Kostya Vasilyev wrote: >>> >>> The children are always numbered starting at 0. >>> >>> The top position may correspond to, erm, 1812'th adapter item, and still >>> be the zero'th child. >>> >>> int nFirst = mAccountListView.**getFirstVisiblePosition(); >>> int nLast = mAccountListView.**getLastVisiblePosition(); >>> for (int position = nFirst; position <= nLast; ++position) { >>> View itemView = mAccountListView.getChildAt(**position - >>> nFirst); >>> ... >>> >>> >>> On 03/10/2012 12:03 AM, RedBullet wrote: >>> > Really? >>> > >>> > So, if I have 100 items in my ListView, and I want to be monkeying >>> > around with item #50 I would do: >>> > getListView().getChild(**getListView().**getFirstVisiblePosition() - >>> 50)) ? >>> > >>> > that doesn't seem right... >>> >>> -- >> >
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