Are you doing this from onCreate? On 03/10/2012 02:00 AM, RedBullet wrote:
And the answer is 0On Friday, March 9, 2012 3:27:08 PM UTC-5, MagouyaWare wrote: What is the value of "index - getListView().getFirstVisiblePosition()"? Thanks, Justin Anderson MagouyaWare Developer http://sites.google.com/site/magouyaware <http://sites.google.com/site/magouyaware> On Fri, Mar 9, 2012 at 1:21 PM, RedBullet <> wrote: OK, so here is my code snipet: RouteAdapter adapter = new RouteAdapter(this, route.getCues()); setListAdapter(adapter); setSelection(); } public void setSelection() { RouteAdapter adapter = (RouteAdapter) getListAdapter(); Integer index = adapter.getPosition(nextCuePoint); View itemView = this.getListView().getChildAt(index - getListView().getFirstVisiblePosition()); The position of the nextCuePoint is 0 (which is correct since it is the first cue). But I am getting null for itemView... On Friday, March 9, 2012 3:11:21 PM UTC-5, Kostya Vasilyev wrote: The children are always numbered starting at 0. The top position may correspond to, erm, 1812'th adapter item, and still be the zero'th child. int nFirst = mAccountListView.getFirstVisiblePosition(); int nLast = mAccountListView.getLastVisiblePosition(); for (int position = nFirst; position <= nLast; ++position) { View itemView = mAccountListView.getChildAt(position - nFirst); ... On 03/10/2012 12:03 AM, RedBullet wrote: > Really? > > So, if I have 100 items in my ListView, and I want to be monkeying > around with item #50 I would do: > getListView().getChild(getListView().getFirstVisiblePosition() - 50)) ? > > that doesn't seem right... -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group athttp://groups.google.com/group/android-developers?hl=en
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