You can have the same id on different widgets. What is the exception you get?
On Tue, Mar 17, 2009 at 12:00 PM, skink <psk...@gmail.com> wrote: > > hi, > > consider the simple layout: > <?xml version="1.0" encoding="utf-8"?> > <LinearLayout > xmlns:android="http://schemas.android.com/apk/res/android"; > android:layout_width="fill_parent" > android:layout_height="fill_parent" > android:orientation="vertical" >> > <LinearLayout > android:layout_width="fill_parent" > android:layout_height="wrap_content" > android:orientation="horizontal" > android:id="@+id/layout0" > > > <Button > android:layout_width="fill_parent" > android:layout_height="wrap_content" > android:id="@+id/child0" > /> > </LinearLayout> > > <LinearLayout > android:layout_width="fill_parent" > android:layout_height="wrap_content" > android:orientation="horizontal" > android:id="@+id/layout1" > > > <ListView > android:layout_width="fill_parent" > android:layout_height="wrap_content" > android:id="@+id/child0" > /> > </LinearLayout> > </LinearLayout> > > i heard its perfectly OK to have the same IDs in different sub-trees > (here layout0/child0 and layout1/child0). > > not really: press ctrl-F12 > > if i change one child to be child1 it works without exception > > is it a droid's bug? > > > -- Romain Guy Android framework engineer romain...@android.com Note: please don't send private questions to me, as I don't have time to provide private support. All such questions should be posted on public forums, where I and others can see and answer them --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en -~----------~----~----~----~------~----~------~--~---
