The garbage collector will take care of freeing it, unless there is something else holding a reference to it (for example inside of your "do stuff" part). You don't need to set buff to null at the end, either.
On Fri, Apr 17, 2009 at 2:01 PM, petunio <[email protected]>wrote: > > Hi > > I know this is more a java question, but I have been in many java > forums, and the theory seems to contradict the real thing... > > I have a very simple function that creates memory, do something with > it, and returns: > > static void test(int k) > { > byte [] buff = new byte[k]; > > //do some stuff with buff[] > > buff=null; > > } > > After a few calls to this function, it runs out memory > In C++ I would use delete at the end, and here in java I've been told > that GC takes care of it, but it seems that it does not > Am I doing something wrong? how can I free this temp memory after I > have used it? > > many thanks > > > -- Dianne Hackborn Android framework engineer [email protected] Note: please don't send private questions to me, as I don't have time to provide private support, and so won't reply to such e-mails. All such questions should be posted on public forums, where I and others can see and answer them. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en -~----------~----~----~----~------~----~------~--~---
