On Apr 17, 2:01 pm, petunio <[email protected]> wrote: > static void test(int k) > { > byte [] buff = new byte[k]; > > //do some stuff with buff[] > > buff=null; > > }
You shouldn't need to set "buff" to null. When the function returns the locals go out of scope and won't be in the root set. Does "do some stuff with buff[]" involve passing buff to other functions? If so, are you sure those other functions aren't hanging on to it? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en -~----------~----~----~----~------~----~------~--~---
